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c) Tim luc ep do con trugt C ep len Ion. 0,3 m i,2 m Hinh 4 Hinh 5 Cau 5: (2.5 diem) Cho he hai banh rang an khdp nhu tren Hinh 5. Biet Ri = 400 mm, R2 = OA = 300 mm. Tai thbi diem khao sat nhu tren hinh ve, tay quay OA va banh rang 1 dang quay ngugc chieu kim dong ho quanh chot ban le co dinh tai O vdi van toe goc tuerng ung la coOA = 1 0 ra d /s va raj = 5 rad/s, hay xac dinh: a) Van t6c cua diem A; c) Tam van toe tuc thcri cua banh rang 2; b) Van toe cua diem B\ d) Van toe goc cua banh rang 2. Cau 6: (1 diem) The disk shown in Figure 6, which has a mass of 20 kg, is subjected to the couple moment o f M = 80 N.m. The radius o f gyration of the disk about its mass center O is kQ- 0,2 m. If the disk starts from rest, determine its angular velocity when it has made 10 revolutions. F igure 6 ___________________________________-HET-______________ Ghi chu: Can bo coi thi khong dupe giai thick de thi. C huan dau ra cua hoc phan (ve kiSn thuc) [CBR 1.1]: Thu gon dugc mot he luc ve mot tam thu gon, phan tich dugc cac thanh phan phan luc lien k it (ke ca luc m a sat) va thiet lap dugc cac phuong trinh can bang cua chat diem, cua vat ran, he vat ran. [CBR 1.2]: Tinh dugc cac thong so dong hgc (vi tri, van toe, gia toe) cua vat ran, diem thuoc vat ran trong chuyen dong song phang. [CBR 1.3]: Su dung dugc phuong phap dong lugng va phuoug phap nang lugng de xac dinh dugc thong s6 dong hgc cua vat ran trong chuyln dong song phang duoi tac dung cua luc. [CBR 2.1]: Phan tich va mo hinh hoa dugc mot so co he tinh dinh trong co khi bang cac mo hinh tinh tuong ung. [CBR 2.2]: Phan tich va mo hinh hoa dugc mot so co cau phang trong co khi bang cac mo hinh tinh tuong ung. [CBR 3.1]: Bgc hieu cac tai lieu co hgc bang tieng Anh. Noi dung k ilm tra Cau 1, 2, 3, 4 Cau 5,6 Cau 6 . Cau 3, 4 Cau 4,5,6 Cau 6 N g a y 10 thang 07 nam 2020 Thong qua b? mon (ky va ghi ro ho ten) S6 hieu: BM 1/QT-PBBCL-RBTV Trang: 2/2 TRUONG DAI HOC SU PHAM KY THUAT THANH PHO HO CHI MINH KHOA CO KHI CHE TAO MAY BO MON CO SO THIET KE MAY DE THI CUOI KY HQC KY 2 NAM HQC 19-20 Mon: O r ky th u a t........................................................ Ma mon hoc: EN M E130620......................................... Be so/Ma de: 0 1 ..................Be thi co 02 trang. Thai gian: 90 phut. Bugc phep sir dung tai lieu: 01 td giay A4 viet tay. Cau 1: (1,5 diem) Mot banh rang chiu lire nhu tren Hinh 1. Biet lire Ft nam trong mat phang Oyz, luc F2nam trong khong gian va co cac toa do goc nhu tren hinh (#<90°). a) Bieu dien cac vector lire tren dudi dang vector Bescartes (theo cac vector don vi i ,j,k ) , b) Tim vector hop lire FR(dudi dang vector Descartes) cua hai lire F{ va F2\ c) Tim do ldn cua vector FR. z Cau 2: (1,5 diem) Tay quay ABC dugc dung de quay true OA nhu tren Hinh 2. True OA nam doc theo true Oy, AB dong thdi vuong goc vdi Oy va BC. Luc F = 200 N tac dung tai C va vuong goc vdi tay cam BC. B ilt 9 = 60° va < j>= 30°. a) Bieu d iin vector luc F dudi dang vector Descartes; b) Tim dang vector Descartes cua moment do luc F gay ra quanh tam O. Cau 3: (l,5.diem ) Beam AB is subjected to the loads and constraints as shown in Figure 3. reactions at A and B. Determine Cau 4: (2,0 diem) Cor cau cua mot may ep Ion dugc mo hinh hoa nhu tren Hinh 4. M ot luc F = 300 N tac dung tai B theo phuorng vuong goc vdi tay cam BC. Bo qua ma sat, hay: a) Ve sor do giai phong lien k it (FBD) cho tay dim ABC; b) Tim phan luc lien k it tai A; S6 hieu: BM 1/QT-PBBCL-RBTV Trang: 1/2